Why voltage drop matters on DC systems
Every foot of wire has a little resistance, and at low voltages that resistance eats a large share of your power. Lose 1 volt on a 120V house circuit and nobody notices. Lose 1 volt on a 12V circuit and you've lost over 8%, enough to make a fridge compressor struggle or a charger shut off.
10.75 is the resistance constant for copper. The 2 accounts for the round trip: current goes out on the positive wire and comes back on the negative. The result is a cross-section in circular mils, which maps to a wire gauge.
Worked example
A 20A load sits 10 feet from the battery on a 12V system, and you want no more than 3% drop (0.36V). (2 × 10.75 × 20 × 10) ÷ 0.36 = about 11,900 circular mils. 10 AWG is 10,380, which is too small, so you'd use 8 AWG at 16,510.
Ampacity: the second check
Short runs can pass the voltage-drop test with wire that's too thin to carry the current safely. A 150A inverter cable that's only 2 feet long might need just 6 AWG for voltage drop, but 6 AWG can't safely carry 150A. The calculator checks both and gives you the thicker answer.
AWG reference
| Gauge (AWG) | Circular mils | Conservative max amps |
|---|---|---|
| 14 | 4,110 | 20 |
| 12 | 6,530 | 25 |
| 10 | 10,380 | 35 |
| 8 | 16,510 | 50 |
| 6 | 26,240 | 65 |
| 4 | 41,740 | 85 |
| 2 | 66,360 | 115 |
| 1/0 | 105,600 | 150 |
| 2/0 | 133,100 | 175 |
| 4/0 | 211,600 | 230 |
Wire with higher-temperature insulation, run in free air, can be rated for more current than this table shows. Bundled wires and hot engine spaces are rated lower. When in doubt, go one size up.